左偏树模板
Xushine研究院一致认为模板才是王道
首先说说左偏树
[性质3] 节点的左子节点右子节点也是一颗左偏树。
#define typec int // type of key val
const int na = -1;
struct node {
typec key;
int l, r, f, dist;
} tr[N];
int iroot(int i) { // find i\’s root
if (i == na)
return i;
while (tr[i].f != na)
i = tr[i].f;
return i;
}
int merge(int rx, int ry) { // two root: rx, ry
if (rx == na)
return ry;
if (ry == na)
return rx;
if (tr[rx].key > tr[ry].key)
swap(rx, ry);
int r = merge(tr[rx].r, ry);
tr[rx].r = r;
tr[r].f = rx;
if (tr[rx].l==na||tr[r].dist > tr[tr[rx].l].dist)
swap(tr[rx].l, tr[rx].r);
if (tr[rx].r == na)
tr[rx].dist = 0;
else
tr[rx].dist = tr[tr[rx].r].dist + 1;
return rx; // return new root
}
int ins(int i, typec key, int root) { // add a new node(i, key)
tr[i].key = key;
tr[i].l = tr[i].r = tr[i].f = na;
tr[i].dist = 0;
return root = merge(root, i); // return new root
}
int del(int i) { // delete node i
if (i == na)
return i;
int x, y, l, r;
l = tr[i].l;
r = tr[i].r;
y = tr[i].f;
tr[i].l = tr[i].r = tr[i].f = na;
tr[x = merge(l, r)].f = y;
if (y != na && tr[y].l == i)
tr[y].l = x;
if (y != na && tr[y].r == i)
tr[y].r = x;
for (; y != na; x = y, y = tr[y].f) {
if (tr[tr[y].l].dist < tr[tr[y].r].dist)
swap(tr[y].l, tr[y].r);
if (tr[tr[y].r].dist + 1 == tr[y].dist)
break;
tr[y].dist = tr[tr[y].r].dist + 1;
}
if (x != na)
return iroot(x); // return new root
else
return iroot(y);
}
node top(int root) {
return tr[root];
}
node pop(int &root) {
node out = tr[root];
int l = tr[root].l, r = tr[root].r;
tr[root].l = tr[root].r = tr[root].f = na;
tr[l].f = tr[r].f = na;
root = merge(l, r);
return out;
}
int add(int i, typec val) // tr[i].key += val
{
if (i == na)
return i;
if (tr[i].l == na && tr[i].r == na && tr[i].f == na) {
tr[i].key += val;
return i;
}
typec key = tr[i].key + val;
int rt = del(i);
return ins(i, key, rt);
}
void init(int n) {
for (int i = 1; i <= n; i++) {
scanf(“%d”, &tr[i].key); //%d: type of key
tr[i].l = tr[i].r = tr[i].f = na;
tr[i].dist = 0;
}
}
看标题我差点当成stl的模板。。
左偏树?好奇怪的名字
好久不玩c#了,,,,